![If sum(r=0)^(n-1)log(2)((r+2)/(r+1)) =prod(r=10)^(99)log(r) (r+1), then 'n' is equal to (A) 4 (B) 3 (C) 5 (D) 6 If sum(r=0)^(n-1)log(2)((r+2)/(r+1)) =prod(r=10)^(99)log(r) (r+1), then 'n' is equal to (A) 4 (B) 3 (C) 5 (D) 6](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/644548240_web.png)
If sum(r=0)^(n-1)log(2)((r+2)/(r+1)) =prod(r=10)^(99)log(r) (r+1), then 'n' is equal to (A) 4 (B) 3 (C) 5 (D) 6
![So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart? So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart?](https://external-preview.redd.it/7EXbmtiqKJm9vW-oXNDRUdM2p9efEPP8QVYep10VtXg.jpg?auto=webp&s=340cdc1a658097201327a258cb96aa518f97be2d)
So Y equals R cubed over three. And if you determine the rate of change in this curve correctly, I think you will be pleasanelty surprised... Well, don't you get it Bart?
![If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to - If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to -](https://dwes9vv9u0550.cloudfront.net/images/3952961/792dfa8e-ee2a-4599-8b84-b82c9bb1d049.jpg)
If Tr = ^2016Crx^2016 - r , for r = 0, 1, ,....2016 , then (T0 - T2 + T4.... + T2016)^2 + (T1 - T3 + T5....T2015)^2 is equal to -
![SOLVED: PPoints R and T are each distance d from each of two equal positive charges as shown Ifk = [/41eo, the work required to move a particle with a negative charge SOLVED: PPoints R and T are each distance d from each of two equal positive charges as shown Ifk = [/41eo, the work required to move a particle with a negative charge](https://cdn.numerade.com/ask_images/65e0695970c94c1da974f651bed9d0da.jpg)
SOLVED: PPoints R and T are each distance d from each of two equal positive charges as shown Ifk = [/41eo, the work required to move a particle with a negative charge
![Point R and T are each a distance d from each of the two particles with equal positive charges as shown. If k = \frac{1}{4 \pi \epsilon_0}, the work required to move Point R and T are each a distance d from each of the two particles with equal positive charges as shown. If k = \frac{1}{4 \pi \epsilon_0}, the work required to move](https://homework.study.com/cimages/multimages/16/es24977278675383053478993.png)